SOLVED: Explain the purpose of the F/M ratio and define F and M in terms of BOD5 and mixed liquor volatile suspended solids.The 500-bed Lotta Hart Hospital has a small activated sludge plant to treat its wastewater. The average daily hospital discharge is 1200 L/day per bed, and the average soluble BOD5 after the primary settling is 500 mg/L. The aeration tank has effective liquid dimensions of 10.0 m wide × 10.0 m long × 4.5 m deep. The plant operating parameters are as follows:MLVSS = 2000 m

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SOLVED: (MandE 6.32) A wastewater treatment plant uses an activated sludge process for secondary treatment of 0.300 m3/s of primary effluent. The mixed liquor has a concentration of 2,100 mg VSS/L, and the RAS concentration is 10,000 mg VSS/L. The substrate concentration in the primary effluent is 220 mg BOD5/L. The F/M ratio for the activated sludge tank is 0.52 mg BOD5*mg VSS-1*d-1, and the cell residence time is 9.0 d.(a) What is the volume of the activated sludge tank? (Answer: 5,220 m3)(b)

Mixed Media Empty Liquor Bottle, Removable Lid, Reusable Bottle, Collectible, Great Gift, Table and Shelf Decor, Unique Vintage Art - Etsy

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